SYMMETRICAL
COMPONENTS
An unbalanced system of n related phasors can be resolved
into n systems of balanced phasors called symmetrical components of the
original phasors.
These symmetrical components are balanced. They are equal in
length and the angle between them are also equal.
In the Electrical Power System, The Symmetrical Components
used, has the Positive Sequence component, the negative Sequence component and the
zero Sequence components.
The characteristic of these components are as follows:
The Positive Sequence component,
The Positive Sequence components consist of three phasors
equal in magnitude displaced from each other by 120o in phase and
having the same phase sequence as the original Phasors. ,
The negative Sequence component,
The negative Sequence components consist of three phasors
equal in magnitude displaced from each other by 120o in phase and
having a phase sequence opposite that of the original Phasors. ,
The Zero Sequence component,
The Zero Sequence Components
consist of three phasors equal in magnitude with zero phase displacement from
each other.
V(a) = V(a1)+V(a2)+V(a0) (i)
V(b) = V(b1)+V(b2)+V(b0) (ii)
V(c) = V(c1)+V(c2)+V(c0) (iii)
Positive Sequence Component
abc(phase sequence of original phasors) ------- abc (phase sequence of
symmetrical components)
Negative Sequence Component
abc(phase sequence of original phasors) -------- acb(phase sequence of symmetrical components)
1=> +ve
2=> -ve
0=> zero
In symmetrical Component Analysis, ‘a’ causes a rotation of
120o
In circuit analysis, ‘j’ causes a 90o rotation
In complex number notation ‘i’ causes a 90o
rotation
In numerical analysis and number notation and representation
‘-1’ causes a 180o rotation
A rotation of 90o + 90o
is achieved by multiplying ‘ j x j ’ which causes a 180o
rotation j2 = -1.
With this understanding,
a = 1/120 = 1ej2π/3
= -0.5 + j0.866
apply ‘a’ twice to achieve a 240o rotation
when ‘a’ is applied three times the phasor is rotated 360o
Hence
a2 = 1/240 = 1ej4π/3
= -0.5 - j0.866
a3 = 1/360 = 1ej2π
= 1/0o = 1
V(b1) = a2V(a1)
V(b2) = aV(a2)
V(b0) = V(a0)
V(c1) = aV(a1)
V(c2) = a2V(a2)
V(c0) = V(a0)
V(a) = V(a1) + V(a2) + V(a0)
V(b) = a2V(a1) + aV(a2) + V(a0)
V(c) =aV(a1) + a2V(a2) + V(a0)
A =
A-1 =
A-1 = 1/3
A-1 = 1/3
V(a0) = 1/3 (V(a) + V(b) + V(c))
V(a10) = 1/3 (V(a) + aV(b) + a2V(c))
V(a20) = 1/3 (V(a) + a2V(b)
+ aV(c))
Let us take a look at the effect of Symmetrical Components
on the Impedance with respect to the Electrical Power System.
V(abc) = Z(abc)I(abc)
Where
Z(abc) 3x3 matrix
giving the self and mutual impedances in and between phases
However
V(abc) = [A]V(012)
I(abc) = [A]I(012)
[A]V(012) = Z(abc)[A]I(012)
Or
V(012) = [A]-1Z(abc)[A]I(012)
Let us define
Z(012) = [A]-1Z(abc)[A]
V(012) = Z(012)I(012)
Power Considerations
We shall apply the Reversal Rule of Matrix Algebra.
The Reversal Rule of Matrix Algebra.
The Reversal Rule Of Matrix Algebra states that the
transpose of the Product of two matrices is equal to the Product of the
transpose of the matrices in reverse order hence :
[AV]T
= VTAT
Complex Power can be expressed as follows in the Electrical
Power System:
S(3φ) = V(a)I*(a) + V(b)I*(b)+ V(c)I*(c)
Let ‘t’ => transpose (interchange of rows and columns
in a matrix v*(i,j) = v(j,i)
)
Let ’*’ =>
conjugate (the mirror image along the x axis of the complex plane of a
complex number or phasor )
In Matrix Notation, This can be written as:
S(3φ) = Vt(abc)I*(abc)
=
{[A]V(012)}t{[A]I(012)} *
=
V(012)tAtA*I*(012)
At A* =
=
Therefore
S(3φ) = 3V(012)t I* (012)
S(3φ) = 3(V(0)I*(0)V(1)I*(1)V(2)I*(2))
Notice that there are no cross terms or mixed quantities in
the expression for S(3φ). This is useful when equivalent circuits are being
considered.
Symmetrical Components are very important in the Analysis of
the Electrical Power System.
It is particularly very useful in the analysis of unbalanced
faults as a result of the unbalanced phasors associated with them.
Name: Nwani Ikechukwu Destiny
ReplyDeleteReg No: Esut/2008/94377
Course: Electrical Power System Analysis (EEE454)
An unbalanced system of N related phasor can be resolved into N system of balanced phasor called symetrical phasor component of the regional phasor. These are equal in length and the distance between them. In electrical power system we have three symetrical components:
1. Positive - sequence component
2. Negative – sequence component
3. Zero – sequence component
Notation
+ve positive sequence component 1
-ve negative sequence component 2
Zero zero sequence component 0
Va = va1 + va2 + va0
Vb = vb1 +vb2 + vb0
Vc = vc1 + vc2 + vc0
Phasor is a vectoral representation of mathematically abstract components but phase represents the three winding lines that make a current. E. g. Red, Yellow, Blue. Etc
Per unit system is a means of normallizing the dimension of electrical quantities
Per unit value=actual value , Vbase Ibase =Sbase
Base value
Modelling is the mathematical representation of electrical quantities.
Assuming infinite conductivity and permeability hence no resistance and no flux leakage.
V1= N1dØ/dt
V2= N2dØ/dt
V3= N3dØ/dt
Name: Onodugo Modestus Onyeka
ReplyDeleteReg.No:ESUT/2010/110891
Course: Electrical Power System Analysis[EEE454]
Symmetrical components:Are balanced phasor used to represent other phasors which may or may not be balanced.It includes,positive,negative and zero symmetrical components.Positive symmetrical component is a type whose phasor phase sequence is the same as those of original phasor(source) and angle of displacement is 120.Negative symmetrical component is a type whose phasor phase sequence is not in the same direction compared to those of the source.Zero is a type whose phasors have equal magnitude and direction but with zero angle of displacement.
Y-Bus Matrix:It is the matrix of admittances used in the analysis of electrical power system.Example is a 2x2 Y-Bus matrix of a 2-bus system.
Load Flow Analysis:It is a study of electrical power system with a view of finding the voltage profile of the system.Its study helps for appropriate system evaluation,maintenance and operation.Among the the following are data s that are necessary for load flow analysis,system topology,system parameters,loading at each system and bus types.Bus is a node at which one or more lines,one or more loads and generators are connected.It includes generator bus,load bus and voltage bus.
fault analysis:It is a study of electrical power system after a fault with a view of determining the voltage and current distribution subsequently.It helps in protection scheme designing and determining of relay tap setting and time dial setting.