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Thursday 14 June 2012

TRANSFORMER CALCULATION

TRANSFORMER CALCULATIONS A single phase transformer has 5000 turns on the Primary winding and 1250 turns on the Secondary. Winding resistances are r(1) = 4 ohms and r(2) = 0.25 ohms. Leakage reactances are x(1) = 16.0 ohms and x(2) = 1.0 ohms . The resistance load Z(2). If applied voltage at the terminals of the primary winding is 1200, find V(2) and the voltage regulation. Neglect magnetising current. Let 'a' be turns ratio. a = N(1) /N(2) = 5000/1250 = 4 R(1) = 4 + (0.25)(4)2 = 4+ (0.25*4*4) = 8 ohms X(1) = 16 + (1)(4)2 = 16+ (1*4*4) = 32 ohms Z'(2) = 24 (4)2 = 384 ohms I(1) = 1200/(384 + 8 + j32) = 1200/393.303954/- 4.6668 = 3.051075/-4.6668 aV(2) = I(1)Z'(2) = 3.051075/-4.6668 *384 =1171.6129/-4.6668 V(2) = aV(2)/a =(1171.6129/-4.6668)/4 = 292.90323/-4.6668 Voltage Regulation Is Given By [{|V(1)/a| -|V(2)|}/|V(2)| ] *100% {(1200/4 ) - 292.9 }/292.9 * 100% = 2.42% lagging

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